2.9 综合练习-IT熊技术站

1.文字版格斗游戏

格斗游戏,每个游戏角色的姓名,血量,都不相同,在选定人物的时候(new对象的时候),这些信息就应该被确定下来,伤害为1~20之间的随机数,当剩余血量为0时,输出K.O语句(名字可以不一样,但是效果必须一致)

图片[1]-2.9 综合练习-IT熊技术站

答案:

[content_hide]

import java.util.Random;  
  
public class person {  
        private String name;  
        private int blood;  
        public person(){  
  
        }  
        public person(String name , int blood){  
               this.name = name;  
               this.blood = blood;  
        }  
        public void setName(String name){  
               this.name = name;  
        }   
        public String getName(){  
               return name;  
        }  
        public void setBlood(int blood){  
               this.blood = blood;  
        }  
        public int getBlood(){  
               return blood;  
        }  
        public void attack(person person){  
               Random r = new Random();  
               int hurt = r.nextInt(20) + 1;  
               int residueBlood = person.getBlood() - hurt;  
               residueBlood = residueBlood < 0 ? 0 : residueBlood;  
               person.setBlood(residueBlood);  
               System.out.println(this.getName() + "举起拳头打了" + person.getName() + 
 "一下,造成了" + hurt + "点伤害," + person.getName() + "还剩下" + residueBlood + "点血");  
        }  
  
}

public class IT梦 {  
      public static void main(String[] args) {  
              person p1 = new person("迪迦奥特曼",100);  
               person p2 = new person("哥尔赞",100);  
               while (true){  
                       p1.attack(p2);  
                      if(p2.getBlood() == 0){  
                              System.out.println(p1.getName() + "K.O了" + p2.getName());  
                              break;  
                      }  
                     p2.attack(p1);  
                     if(p1.getBlood() == 0){  
                              System.out.println(p2.getName() + "K.O了" + p1.getName());  
                              break;  
                      }  
               }  
        }  
}

图片[2]-2.9 综合练习-IT熊技术站

[/content_hide]

2.对象数组1

定义数组存储三个商品对象;

商品的属性:商品的id,名字,价格,库存

创建三个商品对象,并把商品对象存入数组当中

答案:

[content_hide]

public class commodity {  
        private String id;  
        private String name;  
        private double price;  
        private int count;  
  
        public commodity() {  
        }  
  
         public commodity(String id, String name, double price, int count) {  
                 this.id = id;  
                 this.name = name;  
                 this.price = price;  
                 this.count = count;  
         }  
  
        public String getId() {  
               return id;  
        }  
  
        public void setId(String id) {  
               this.id = id;  
        }  
  
        public String getName() {  
               return name;  
        }  
  
        public void setName(String name) {  
               this.name = name;  
       }  
  
        public double getPrice() {  
                return price;  
        }  
  
        public void setPrice(double price) {  
                this.price = price;  
       }  
  
       public int getCount() {  
                return count;  
      }  
  
       public void setCount(int count) {  
               this.count = count;  
       }  
}

public class IT梦 {  
      public static void main(String[] args) {  
             commodity []arr = new commodity[3];  
             commodity c1 = new commodity("001" , "电脑" , 7999.0 , 50);  
             commodity c2 = new commodity("002" , "手机" , 5999.0 , 100);  
             commodity c3 = new commodity("003" , "键盘" , 199.0 , 1000);  
             arr[0] = c1;  
             arr[1] = c2;  
             arr[2] = c3;  
             for (int i = 0; i < arr.length; i++) {  
                     commodity c = arr[i];  
                     System.out.println(c.getId() + ", " + c.getName() + ", " + c.getPrice() + ", " +  c.getCount());  
            }  
       }  
}

图片[3]-2.9 综合练习-IT熊技术站

[/content_hide]

3.对象数组2

定义数组存储3部汽车对象

汽车的属性:品牌,价格,颜色

创建三个汽车对象,数据通过键盘录入而来,并把数据存入到数组当中

键盘录入拓展:

第一套体系(遇到空格,制表符,回车就停止接收):

1. nextInt();——-接收整数

2. nextDouble();——-接收小数

3. next();——-接收字符串

第二套体系(可以接收空格,制表符,遇到回车才停止接收数据):

1. nextLine();——-接收字符串

注:键盘录入的两套体系不能混用的

弊端:先用nextInt,再用nxetLine会导致下面的nextLine接收不到数据

答案:

[content_hide]

public class car {  
	private String brand;  
	private double price;  
	private String color;  
  
	public car() {  
	}  
  
	public car(String brand, double price, String color) {  
		this.brand = brand;  
		this.price = price;  
		this.color = color;  
	}  
  
	public String getBrand() {  
		return brand;  
	}  
  
	public void setBrand(String brand) {  
		this.brand = brand;  
	}  
  
	public double getPrice() {  
		return price;  
	}  
  
	public void setPrice(double price) {  
		this.price = price;  
	}  
  
	public String getColor() {  
		return color;  
	}  
  
	public void setColor(String color) {  
		this.color = color;  
	}  
}

import java.util.Scanner;  
  
public class IT梦 {  
	public static void main(String[] args) {  
		car[] arr = new car[3];  
		Scanner sc = new Scanner(System.in);  
		for (int i = 0; i < arr.length; i++) {  
			car c = new car();  
			System.out.println("请输入第" + (i + 1) + "辆汽车的品牌");  
			String brand = sc.next();  
			c.setBrand(brand);  
			System.out.println("请输入第" + (i + 1) + "辆汽车的价格");  
			Double price = sc.nextDouble();  
			c.setPrice(price);  
			System.out.println("请输入第" + (i + 1) + "辆汽车的颜色");  
			String color = sc.next();  
			c.setColor(color);  
			arr[i] = c;  
		}  
		for (int i = 0; i < arr.length; i++) {  
			car c = arr[i];  
			System.out.println(c.getBrand() + ", " + c.getPrice() + ", " + c.getColor());  
		}  
	}  
}

[/content_hide]

图片[4]-2.9 综合练习-IT熊技术站

4.对象数组3

定义数组存储3部手机对象

手机的属性:品牌,价格,颜色

要求,计算出三部手机的平均价格

答案:

[content_hide]

public class phone {  
	private String brand;  
	private int price;  
	private String color;  
  
	public phone() {  
	}  
  
	public phone(String brand, int price, String color) {  
		this.brand = brand;  
		this.price = price;  
		this.color = color;  
	}  
  
	public String getBrand() {  
		return brand;  
	}  
  
	public void setBrand(String brand) {  
		this.brand = brand;  
	}  
  
	public int getPrice() {  
		return price;  
	}  
  
	public void setPrice(int price) {  
		this.price = price;  
	}  
  
	public String getColor() {  
		return color;  
	}  
  
	public void setColor(String color) {  
		this.color = color;  
	}  
}

public class IT梦 {  
	public static void main(String[] args) {  
		phone[] arr = new phone[3];  
		phone p1 = new phone("小米",5000,"黑色");  
		phone p2 = new phone("华为",6000,"白色");  
		phone p3 = new phone("苹果",10000,"蓝色");  
		arr[0] = p1;  
		arr[1] = p2;  
		arr[2] = p3;  
		int price = p1.getPrice() + p2.getPrice() + p3.getPrice();  
		int meanPrice = price / arr.length;  
		for (int i = 0; i < arr.length; i++) {  
			phone p = arr[i];  
			System.out.println(p.getBrand() + ", " + p.getPrice() + ", " +                     p.getColor());  
		}  
		System.out.println("三部手机的平均价格为:" + meanPrice);  
	}  
}

图片[5]-2.9 综合练习-IT熊技术站

[/content_hide]

5.对象数组4

定义数组存储4个女朋友对象

女朋友的属性:姓名,年龄,性别,爱好

要求1:计算出4个女朋友的平均年龄

要求2:统计年龄比平均值低的女朋友有几个,并把他们的信息打印出来

答案:

[content_hide]

public class girlFriend {  
	private String name;  
	private int age;  
	private char gender;  
	private String hobby;  
  
	public girlFriend() {  
	}  
  
	public girlFriend(String name, int age, char gender, String hobby) {  
		this.name = name;  
		this.age = age;  
		this.gender = gender;  
		this.hobby = hobby;  
	}  
  
	public String getName() {  
		return name;  
	}  
  
	public void setName(String name) {  
		this.name = name;  
	}  
  
	public int getAge() {  
		return age;  
	}  
  
	public void setAge(int age) {  
		this.age = age;  
	}  
  
	public char getGender() {  
		return gender;  
	}  
  
	public void setGender(char gender) {  
		this.gender = gender;  
	}  
  
	public String getHobby() {  
		return hobby;  
	}  
  
	public void setHobby(String hobby) {  
		this.hobby = hobby;  
	}  
}

public class IT梦 {  
	public static void main(String[] args) {  
		girlFriend []arr = new girlFriend[4];  
		girlFriend g1 = new girlFriend("小美",18,'女',"打羽毛球");  
		girlFriend g2 = new girlFriend("小丽",21,'女',"瑜伽");  
		girlFriend g3 = new girlFriend("小爱",19,'女',"游泳");  
		girlFriend g4 = new girlFriend("小刘",22,'女',"爬山");  
		arr[0] = g1;  
		arr[1] = g2;  
		arr[2] = g3;  
		arr[3] = g4;  
		int age = g1.getAge() + g2.getAge() + g3.getAge() + g4.getAge();  
		int meanAge = age / arr.length;  
		System.out.println("平均年龄为:" + meanAge);
		int count = 0;  
		for (int i = 0; i < arr.length; i++) {  
			girlFriend g = arr[i];  
			if(g.getAge() < meanAge){ 
				count++; 
				System.out.println(g.getName() + ", " + g.getAge() + ", " + g.getGender() + ", "  + g.getHobby());  
			}  
		}
		 System.out.println("比平均年龄低的一共有" + count + "个"); 
	}  
}

图片[6]-2.9 综合练习-IT熊技术站

[/content_hide]

6.对象数组5

定义一个长度为3的数组,数组存储1~3名学生对象作为初始数据,学生对象的学号,姓名各不相同

学生的属性:学号,姓名,年龄

要求1:再次添加一个学生对象,并在添加的时候进行学号的唯一性判断

要求2:添加完毕后,遍历所有学生信息

要求3:通过学号删除学生信息

如果存在,则删除,如果不存在,则提示删除失败

要求4:删除完毕后遍历所有学生信息

要求5:查询数组学号为1的学生,如果存在,则他的年龄+1岁

答案:

[content_hide]

public class student {  
	private int id;  
	private String name;  
	private int age;  
  
	public student() {  
	}  
  
	public student(int id, String name, int age) {  
		this.id = id;  
		this.name = name;  
		this.age = age;  
	}  
  
	public int getId() {  
		return id;  
	}  
  
	public void setId(int id) {  
		this.id = id;  
	}  
  
	public String getName() {  
		return name;  
	}  
  
	public void setName(String name) {  
		this.name = name;  
	}  
  
	public int getAge() {  
		return age;  
	}  
  
	public void setAge(int age) {  
		this.age = age;  
	}  
}

public class IT梦 {  
	public static void main(String[] args) {  
		student[] arr = new student[3];  
		student s1 = new student(1,"小明",18);  
		student s2 = new student(2,"小亮",19);  
		student s3 = new student(3,"小鹏",20);  
		arr[0] = s1;  
		arr[1] = s2;  
		arr[2] = s3;  
		student s4 = new student(4,"小张",19);  
		boolean flag = decideId(arr,s4.getId());  
		if(flag){  
			System.out.println("该id已存在,请重新输入id后添加");  
		}else {  
			int count = getcount(arr);  
			if(count == arr.length){  
				student[] newArr = getNewArr(arr);  
				newArr[count] = s4;  
				System.out.println("添加后的所有学生信息");  
				printArr(newArr);  
			}else {  
				arr[count] = s4;  
				System.out.println("添加后的所有学生信息");  
				printArr(arr);  
			}  
		}  
		int index = getIndex(arr,2);  
		if(index >= 0){  
			arr[index] = null;  
			System.out.println("------------------");  
			System.out.println("删除后的所有学生信息:");  
			printArr(arr);  
		}else {  
				System.out.println("删除失败");  
		}  
		int newIndex = getIndex(arr,1);  
		if(newIndex >= 0){  
			student s = arr[newIndex];  
			int newAge = s.getAge() + 1;  
			s.setAge(newAge);  
			System.out.println("------------------");  
			System.out.println("修改年龄完后的所有学生信息:");  
			printArr(arr);  
		}else {  
			System.out.println("当前id不存在,无法修改");  
		}  
	}  
	public static int getIndex(student[] arr,int id){  
		for (int i = 0; i < arr.length; i++) {  
			student s = arr[i];  
			if(s != null){  
				if(s.getId() == id){  
					return i;  
				}  
			}  
		}  
		return -1;  
	}  
	public static void printArr(student[] arr){  
		for (int i = 0; i < arr.length; i++) {  
			student s = arr[i];  
			if(s != null){  
				System.out.println(s.getId() + ", " + s.getName() + ", " +                         s.getAge());  
			}  
		}  
	}  
	public static student[] getNewArr(student[] arr){  
		student[] newArr = new student[arr.length + 1];  
		for (int i = 0; i < arr.length; i++) {  
			newArr[i] = arr[i];  
		}  
		return newArr;  
	}  
	public static int getcount(student[] arr){  
		int count = 0;  
		for (int i = 0; i < arr.length; i++) {  
			if(arr[i] != null){  
				count++;  
			}  
		}  
		return count;  
	}  
	public static boolean decideId(student[] arr , int id){  
		for (int i = 0; i < arr.length; i++) {  
			student s = arr[i];  
			if(s != null){  
				if(s.getId() == id){  
					return true;  
				}  
			}  
		}  
		return false;  
	}  
}

图片[7]-2.9 综合练习-IT熊技术站

[/content_hide]

文章版权声明 1、本网站名称：IT熊技术站
2、本站永久网址：https://www.cutrui.cn
3、本网站的文章部分内容可能来源于网络，仅供大家学习与参考，如有侵权，请联系站长进行删除处理。
4、本站一切资源不代表本站立场，并不代表本站赞同其观点和对其真实性负责。
5、本站一律禁止以任何方式发布或转载任何违法的相关信息，访客发现请向站长举报
6、根据《计算机软件保护条例》第十七条，本站所有软件请仅用于学习研究用途

THE END